Calculating Inch Pounds for an Iron Cross (link)

Calculating Inch Pounds for an Iron Cross.

Yours in Fitness,

Coach Sommer

So it is

((length of your arm * your weight)/2) * 2?

You said the division by two was because you are using both arms, what is the multiplication for?

EDIT:

Nevermind, I had the parenthesis at the wrong part I think.

It's

(length of your arm * (your weight/2)) * 2?

That's just the formula for the amount of torque being exerted on your shoulders. But in order for that to be accurate, you would need to take into account the length of the straps and the angle at which they are at with respect to vertical.

Wangtang6911 said:

That's just the formula for the amount of torque being exerted on your shoulders. But in order for that to be accurate, you would need to take into account the length of the straps and the angle at which they are at with respect to vertical.

Yes, you do have to take into account strap length and angle. That's the one thing that's overlooked most of the time even though practically speaking it's obvious that shorter cables/greater angle = easier.

In addition, it's torque on the shoulders, but it's not the forces that are exerted by the muscles themselves.

Since we all have different muscle insertion points you'd have to recalculate based on the ratios and angles of the insertion of your muscles.

People with insertions that are a bit farther down on the humerus will have to exert less force to do a cross than people with insertions closer to the head of the humerus.

This is why there's a whole field on biomechanics.